• @[email protected]
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    411 year ago

    Could be easily made 50% space saving by only iffin all odds and return even on else. Maybe one if before to handle overflow to avoid wrong even if over the last if.

    • bjorney
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      18
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      1 year ago

      Yeah but then ALL even numbers would be slow to compute because you would have to chain through every odd before you know that 2 is even.

      Depends on the expected distribution of input values

      • @[email protected]
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        11 year ago

        Heuristic: keep it until 512, afterwards powers of 2, and numbers like 1000, 2000,…, 10000, 20000,… (regex: [0-9]000+)