• @[email protected]
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    834 months ago

    Though photons don’t have mass, they can force momentum when they hit an object — that’s what a solar sail takes advantage of.

    Sounds like a bug.

      • @[email protected]
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        24 months ago

        Either way, NASA is already exploiting it. I guess, next they’ll find a way to glitch through the very fabric of the universe to teleport to a distant galaxy without moving at all or even using any energy.

      • @[email protected]
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        374 months ago

        In short, even though photons have no mass, they still have momentum proportional to their energy, given by the formula p=E/c. Because photons have no mass, all of the momentum of a photon actually comes from its energy and frequency as described by the Planck-Einstein relation E=hf.

        From here: https://profoundphysics.com/if-photons-have-no-mass-how-can-they-have-momentum/

        Essentially, momentum is a function of energy, not mass. It’s just that massive objects have way more momentum than massless ones.

        • @[email protected]
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          4 months ago

          Essentially, momentum is a function of energy, not mass.

          Thanks! That’s the critical piece of information.

      • @[email protected]
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        104 months ago

        Because they have mass. They don’t have “mass at rest”, but they are never at rest anyway.

        Do you remember that famous E = mc^2 equation? Everything that has energy has mass.

        • @[email protected]
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          4 months ago

          But how do you apply this with Lorentz’ transformation (i.e. relativistic factors)? You cannot approach the speed of light without considering relativism. It is known that p = gamma * m * v where p is momentum, gamma is the gamma factor given by sqrt(1/(1 - (v^2/c^2))), m is mass and v is velocity. If you study the gamma factor, you’ll realize that it approaches infinite as v approaches c, the speed of light. Since we are actually dealing with light here, where v = c we are breaking the equation. Momentum cannot be defined for any mass which moves at the speed of light. It’s asymptotic at that speed.

          Also note that the same goes for E = mc^2. At relativistic speeds, also this equation needs to consider the gamma factor. So those classical equations break down for light.

          The answer is that photons don’t have mass, but they have energy. There is a good explanation a bit further up in this thread on how this is possible.

          • @[email protected]
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            14 months ago

            The one that you multiply with gamma is the rest mass, not the total mass.

            To be short, p = m_0 * γ * v, where m_0 is the rest mass. Put that in your equation and look what happens.

          • @[email protected]
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            24 months ago

            They can also be created or absorbed into something else. The mass of whatever absorbs them increases, and the mass of whatever is emitting them decreases when they do that.

            The mass of everything is changing all the time. The thing that is constant is the rest mass.

            • @[email protected]
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              54 months ago

              The object doesn’t absorb their mass, but rather their energy (which admittedly can be equated to a mass via a factor of c^2, but that’s not actually what’s happening). The change in momentum that results from a photon hitting you isn’t caused by a change in m, it comes from a change in v. If mass were the quantity being transferred, solar sails wouldn’t work to move anything; they would just sit there and get more massive as photons hit them.

      • Richard
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        164 months ago

        Radiation pressure does not have anything to do with mass-energy equivalence. 1), the energy for this process does not come from the conversion of electric energy into mass, and 2) having a momentum is not a property tied to massive particles. All electromagnetic waves carry momentum according to Maxwell’s theory of electromagnetism, and its transfer is fully explained by his equations and results from the interaction of the EM wave with matter, i.e., absorption and reflection. Each such interaction will transfer momentum to the massive object. This is classical physics, you don’t need any Einstein relativity to explain electromagnetic phenomena because his theories only become relevant for very massive bodies and their movement, and nuclear reactions.

        • subignition
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          54 months ago

          ok, that’s quite far over my head but I will take your word for it

          • @[email protected]
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            4 months ago

            Ok, a side note on etiquette here.

            When I saw this reply it had a point score of 0, which means somebody downvoted the post.

            When a user is freely admitting a lack of expertise, and defers to another user who seems to know better, I would say it’s extremely rude to downvote that reply.

            This is an example of a user going out of their way to humbly rescind their previous statements when it appears they were mistaken (this is admirable and not a thing that usually happens on the Internet). They didn’t do it for their own benefit, but for the benefit of the community, to not leave misleading or incorrect information in the comments.

            So to sum up, downvoting a selfless act is pretty shitty and not good for the community.

            • subignition
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              24 months ago

              in fairness, I was terse in my original response and probably came off as insincere. Thank you though. I try not to leave up misinformed statements when it turns out to be a learning moment.